What is the distance between two ships?

Question

Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30º and 45º respectively. If the lighthouse is 100 m high, the distance between the two ships is:

Answer 1

sin 30 = 1/2 and sin x = Perpendicular/Hypoteneous.
so,
Perpendicular =100m
Hypoteneous=100/sin30=100*2=200

Now, Base1=sqrt(sqr(200)-sqr(100))=173.32

Similarly
Hypoteneous2 = Perpendicular/Sin 45 = 100*1.414=141.4
Base2=sqrt(sqr(141.4)-sqr(100))=99.96

Distance=Base1+Base2=173.76+99.96=273 m apporx

Answer: Distance = 273 m (approx)