If x^4 + 5y = 6 x^2 y^2 + 5x = 6 Then x,y=??
Its simple Answer will be x,y = 1
1^4 + 5*1 = 6 1^2 1^2 + 5*1 =6
we have x^4 + 5y = 6 x^2 y^2 + 5x = 6 this is possible only when x=1 and y=1
If 2^x = 3^y = 6 then which of the following statements is true?
1) x - y = xy 2) y - x = xy 3) x + y = xy 4) xy = x/y
x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be
