A cistern has a leak which would empty it in 8 hours. A tap is turned on which admits 6 litres a minute into the cistern and it is now emptied in 12 hours. How many litres does the cistern hold?
cistern has a leak which would empty it in 8 hours => Leak rate per hour = 1/8 cistern or say x/8 (x is the capacity of cistern)
Now from the second statement => x/8 - 6 = x/12 => x/8-x/12 = 6 => x/24 = 6 => x=144 Ltr
So cistern capacity is 144 ltr
Pipe A can fill a cistern in 4 hours while pipe B can empty it in 6 hours. If both of them are opened together at the same time when the tank is empty, then how many hours would be taken by them to fill it?
A leak in the bottom of the tank can empty it in 8 hours. An inlet pipe fills the tank at the rate of 6 liters per minute. When the tank is full, the inlet is opened but leak emptied the tank in 9 hours. What is the capacity of the tank?
A cistern has three pipes A, B and C. The pipes A and B can fill it in 4 and 5 hours respectively and C can empty it in 2 hours. If the pipes are opened in order at 1, 2 and 3 am respectively.. When will the cistern be empty?
With uniform flow taps A and B can fill tank in 4 and 3 hours respectively. Tap C can empty the completely the filled tank in one and half hour. Tap A is opened at 9:30 am, tap B is opened at 10:15 am and tap C is opened at 11 am. At what exact time will the tank be empty?
A tap can fill a cistern in 11 hours, but due to a leakage it took 13 hours to fill the cistern. If the cistern is full, in what time will the cistern become empty due to leakage?