A bag contain 5 blue and 4 black balls. Three balls are drawn at random. What is the probability that 2 are blue and 1 is black.
n(S)=9C3 n(E)=(5C2*4C1)
p(E)=n(E)/n(S) =(5C2*4C1)/9C3........simplify
P(E)=10/21
Ans is 10/21 probability
probability=10/21
p(E)= 5c2 *4c1 / 9c3 = 10/21
A bag contains 5 white, 4 red and 3 black balls. A ball is drawn at random from the bag, what is the probability that it is not black?
A bag contains 4 yellow, 5 red, 3 green and 4 black balls. If 4 balls are drawn randomly without replacement, what is the probability that the balls drawn contains balls of different colors?
A bag contains Red Balls and Black Balls. Two balls are drawn without replacement. The probability that both the balls drawn are red is 1/2. What is the minimum number of Red and Black Balls for which this probability is satisfied?
A bag contain 5 red balls and some blue balls. If the probability of drawing a blue ball from the bag is four time that of a red ball, then find the number of blue balls in the bag.
