Two circles are drawn inside a square with side length as 2 + SQRT(2) as shown in the figure.

Question

Two circles are drawn inside a square with side length 2 + SQRT(2) as shown in the figure. Let the radius of the larger circle be R and the radius of the smaller circle be r . Find the value of R + r

Answer 1

Answer is sqrt 2

Comments

How did you came out whith this answer ?

Answer 2

A very interesting problem, took me some time to solve it, the total magnitud of the side length is 4 since 2+SQRT(2) is + & - (1.4142) so 2+ SQRT(2) + ( - SQRT (2) = 4 this give the diameter of the a circle that cover 2R + 2r and haft of it is the radius (R+r) so the answer is 2. At first you will take the sides to be 2 + 1.4142 but this is only part of the "picture" you will have to ADD the second component in the original question (2 - 1.4142) = 0.5858
" For the Universe to exist, there MUST be an oppsosite mirror image of Ours"

Answer 3

ans is 1.74

as length of the hypotenuse will be 4.2020
again R√2 + R + r+ r√2 = 4.2020
on solving we'll get R+r = 1.74

Answer 4

The solution for above question

Answer 5

Answer is SQRT 2 +1

Comments

Can you show how did you came to this ?