26 1/4 days
If B can do x amount of work in 21 days then A can 3x amount of work in 21 days. Solve for x: A + B = 21 days therefore 3x + x = 21 days 4x = 21 days x = 21/4 days x = 5 1/4 days
If B is not there then A has to do their work and B's work therefore it will take A 21 days + 5 1/4 days = 26 1/4 days
B is more efficient than A and they together can complete a work in 18 days. Had A done 60% of the work and then B, the remaining work, then the work would have been completed in 39 days. B alone will complete 60% of the same work in how many days?
B alone can complete the work in 45 days. A is 35% more efficient than B. If A and B together started the work but after 18 days A and B left. Then C alone completed the remaining work in 3 days. If they get Rs. 9750 as wages for the whole work, then what is the share of C in wages for the remaining work?
A can work 4/3 as fast as B and C together. A and B together can work 6 times as fast as C. If all three of them complete a job in 100/7 days, then how long would B alone take to complete the same work (in days)?
You, he and I together do a piece of work in 1 hour. If you do twice as much work as I, and if you alone require 1 hour more than he alone to perform the work, in what time can each alone do the work?
