The sum of the digits of a three digit number is 17, and the sum of the squares of its digits is 109. If we subtract 495 from the number, we shall get a number consisting of the same digits written in the reverse order. Find the number.
Ans:The three digit number is 863. (8+6+3)=17 (8^2+6^2+3^2)=(64+36+9)=109 863-495=368..........(368 is reverse of 863).
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