Question

5 friends live in the same road A, B, C, D, E. The numbers of B, C, D when multiplied together equals 1260. The numbers B,C, D when added equal twice E’s number, and is even. A’s number is half as much again as E’s. The road numbers run from 2 to 222. What are the 5 house numbers?

Answer 1

A- 36, B- 4, C- 9, D- 35, E- 24 one of solutions

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BCD=1260 --- (1)
B+C+D = 2E --- (2) and E has to be even. Hence, sum of B, C and D must be even number such that (B+C+D)/2 is also even.
A = 0.5(B+C+D+E) which implies 2A = 3E --- (3)
By prime factorization, 1260 = 22 ´ 32 ´ 5 ´ 7
By permutation of B, C and D such that product of BCD will give 1260, there are a couple of acceptable answers.

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Note that there are other possible solutions as B, C, D are interchangeable answers.