How many five digit numbers can be formed from the digits, 2, 3, 4, 5, 6, 7, 8 and 9 with no digit repeated?

Question

How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 0, which are divisible by 5 and none of the digits is repeated?

Answer 1

Given digit are 2,3,4,5,6,7,8,9

Total digit =8
we contain only five digit at a time so total ways,and not any digit repeated

By permutation 8P5=8!/(8-5)!
=6720