Can you solve the below algebraic mathematical equation? (J+O+I+N+T)3 = JOINT

Question

Can you solve the below Algebraic equation?

Answer 1

(1+9+6+8+3)^3= 19683

---

This must be (J+O+I+N+T)^3=JOINT
the answer would be J+O+I+N+T= 2 digit number, in power 3 so that the resultant number has 5 different digits with the sum being equal to that 2-digit number. 27 is a such number that gives 19683 in power 3, sum of its digits equals to 27.
(1+9+6+8+3)^3= 19683