if 3+4=21 , 5+6=55 , 2+7=18 then 6+8=?

Question

if 3+4=21 , 5+6=55 , 2+7=18 then how much is 6+8=?

Answer 1

Thanks for the query.

The answer should be 84.

The equations are in the format of Sum of the two numbers * the first number.
So, 3 +4 => Sum of the numbers * the first number = 7*3 = 21
Similarly the others.

Therefore, 6 + 8 => 14*6 = 84

Answer 2

6+8=14
14*6=84
so 84 is the answer.

Answer 3

14x6=84
`6+8=14

Answer 4

Answer is 84
The logic behind is:
sum of 2 numbers(first no. and second no.) * first number = result
3+4=21
=>> (3+4) * 3 = 7 * 3 = 21
5+6=55
=>> (5+6) * 5 = 11 * 5 = 55
2+7=18
=>> (2+7) * 2 = 9 * 2 = 18
6+8=84
=>> (6+8) * 6 = 14 * 6 = 84

Answer 5

3*(3+4)=21
5*(5+6)=55
2*(2+7)=18
6*(6+8)=84

Answer 6

if 3+4=21 that is 3+4=7 and 7*3=21
6+8=86

Answer 7

84
6+8=14; 14*6=84
6+8=84

Answer 8

(3+4)*3=21 (5+6)*5=55 (2+7)*2=18 (6+8)*6=84
ANS: 84