A contractor took a job for his group to do in 20 days. But 12 men did not come up for the job and job was done by remaining man in 32 days. What was the original size of the contractor’s team?
If the initial workforce = N. It's given that N people completed 1 job in 20 days and (N-12) people completed the same job in 32 days. Work speed of N people = (1 job / 20 days)=(1/20) Work speed of a person = (1 job / (20 days*N))=(1/(20*N)) Work speed of 12 people = (1 job / 20 days)*(12/N) =12/(20*N) Work speed of (N-12) people = (1/20)-(12/(20*N)) = 1/32 Rearranging for N gives N = 32. That means the initial workforce consisted of 32 people.
20x=(x-12)*32 X=32
8 woman and 12 men complete a certain piece of work in 9 days. Each woman takes twice the time taken by a man to finish the work. In how many days will 12 men finish the same work
Nine men can finish a work in 20 days whereas 12 women can finish the same work in 18 days. If 6 men and 9 women started working together. After 8 days 3 women left and 2 new men joined the work, the group continued working together till the end of the work. In how many days they would be able to do the remaining work?
If 9 boy working 15/2 hours a day can finish a work in 20 days, then how many days will be taken by 12 boy working 6 hours a day to finish the work, it being given than 3 boy of latter type work as much as 2 boy of he former type in the same.
Certain work is proposed to be completed in 54 days with 30 men. But after 36 days it is observed that only 40% of the work is completed. How many more men are required to complete the work in stipulated time?
