a=2/3b=2/3c=d/3=e=f/2 abc=(f/2)x(3/4f)x(3/4f) = 9/32f3 def=(3/2f)x(f/2)x(f)=3/4f3 abc/def=(9/32)/(3/4)=3/8
3/8 (a/b)*(b/c)*(c/d)=(2/3)*(1)*(1/2)=a/d=1/3 (b/c)*(c/d)*(d/e)=(1)*(1/2)*(3)=b/e=3/2 (c/d)*(d/e)*(e/f)=(1/2)*(3)*(1/2)=c/f=3/4 multiply the three=a.b.c/(d.e.f)=3/8
another way of solving the same is let a=2, then b=3, c=3, d=6,e=2 and f=4. now a.b.c/(d.e.f)=2*3*3/(6*2*4)=3/8
If a/b = 21/34; b/c = 121/120; c/d = 17/77; e/f = 11/15 and d/e = 14/17 then what is the value of (abc/def)*2?