Which is the smallest number of five digits which is divisible by 15, 27 and 35?

Question

A 50 digit number, divisible by 13, is as follows -

Find the value of m.

Answer 1

15×27×35 = (3×5)×(3×3×3)×(5×7)

It seems that the smallest subset needed could be:

3×3×3×5×7 = 945

and to get the first 5-digit number having this set of divisors:

945 × 11 = 10 395