1111=4=fouR 2222=8=eighT 3333=12=twelvE 4444=16=sixteeN 5555=20=twentY
So answer is Y
1*4=4 fouR 2*4=eighT 3*4=twelvE 4*4=sixteeN 5*4=twentY
R
T
E
N
Y
1111=r 2222=t 3333=e 4444=n 5555=y
Y........................................................
Answer is Y 5+5+5+5=20=twentY
1111=1+1+1+1=FOU(R) similarly ,2222=EIGH(T)=T, 3333=TWELV(E)=E, 4444=SIXTEE(N)=N Then 5555TWENT(Y)=Y.
answer is Y. ENTRY (jumbled words R T E N and Y) Y is the missing alphabet.
if 1+1+1+1=4 in word FOUR last word id R and 2+2+2+2=8 in word EIGHT LAST WORD IS T 3+3+3+3=12 IN WORD TWELVE LAST WORD IS E 4+4+4+4=16 IN WORD SIXTEEN LAST WORD IS N 5+5+5+5=20 IN WORD TWENTY LAST WORD IS Y SO ANSWER IS Y
Y. 1111=4, whose last letter is R 2222=8, whose last letter is T and so on.
Its Y .................so simple
If 1111=FR, 2222=ET, 3333=TE, 4444=SN Then 6666=??
