If A = 1 B = 2 C = 3 ... ... Z = 26.
Based on above rule, you need to find an eleven letter word whose letter sum is equal to 52.
Ans is abracadabra
Answer: abracadabra a=1; b=2 c=3 d=4 r=18 1+2+18+1+3+1+4+1+2+18+1=52
I am a five letter word namely, 1 2 3 4 5...... which is under you, If you put out 1, its above you, If you put out 1 and 2, its around you. What am I?
