Assume its a hexadecimal system then 2+4+5+6+7+8=20 (32 in decimal is 20 in hexadecimal)
The digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 can be arranged into an addition sum to add up to almost any total, except that nobody has yet found a way to add up to 1984. However 9 digits can equal 1984 by an addition sum. Which digit is omitted?
In the following sum the digits 0 to 9 have all been used, O = Odd, E = Even, zero is even and the top row's digits add to 9. Can you determine each digit?
There is a unique number which when multiplied by any number from 1 to 6, we will get the new number that contains same digits only.
Can you find that number ?
Use the digits 1, 2, 3, 4, 5 and 6 once only, in this multiplication sum to make it correct.
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