If, 29 - 1 = 30 9 - 1 = 10 14 - 1 = 15
Based on similar logic, Can you prove that the below algebraic equation is true? 11 - 1 = 10 ?
This is meaningful only if we convert every number here into their roman number equivalents and subtract 1 by removing I from the number. 29 - 1 = 30 XXIX - I = XXX (Roman equivalent of number 30) 14 - 1 = 15 XIV - I = XV (Roman equivalent of number 15) 9 - 1 =10 IX - I = X (Roman equivalent of number 10) Hence, 11 - 1 = 10 XI - I = X (Roman equivalent of number 10).
Can you solve the popular algebraic equation by replacing alphabets with a digit and equation must be true as well? SEND + MORE ====== MONEY
If the following is true, can you find the value of (4 + 9)?
7 + 7 = 2 8 + 8 = 4 8 + 5 = 1 6 + 9 = 3 10 + 11 = 9
Can you solve the below Algebraic equation?
Fill below squares with all the integers from 1 to 18 (using each number only once), such that each equation holds true?