28 x 23 = 644 , so B = 2.
(10*B+8)*(10*B+3)=644=>100*(B^2)+110*B-620=0 =>10B^2+11B-62=0, A quadratic equation,=> two solutions, one real=>B=2, Another imaginary.
In the equation below A, B & C represent different digits.
Can you find their value from the given information?
√a + b = 7 √b + a = 11
Provide your working also?
Can you solve the equation by finding the value of A) Horse B) Cowboy boot C) Horseshoe
In the Picture?
