If 1,4,3=13; 4,5,4=9; 5,6,5=11 and 7,7,6=7 then 9,8,7=?
1 is the answer 1,4,3=13 4-1=3 3×3=9 9+4=13 like this 8-9=-1 -1x7=-7 -7+8=1 so, 1 is the answer
Hopefully this will help someone. 1,4,3=13 4-1=3 3×3=9 9+4=13
Answer should be 1
1,4,3 - 1st number, 2nd number and 3rd number
(2nd number - 1st number) x 3rd number + 2nd number
(4 - 1) x 3 + 4 = 13 (5 - 4) x 4 + 5 = 9 (6 - 5) x 5 + 6 = 11 (7 - 7) x 6 + 7 = 7 (8 - 9) x 7 + 8 =1
Can also be solved as A, B, C
B squared - (A * C)
(4×4) - 1 × 3 = 13 (5×5) -4 × 4 = 9 (6×6) - 5 × 5 = 11 7 × 7 - 7 × 6 = 7 8 × 8 - 9 × 7 = 1ans So right ans is 1
If the following is true, can you find the value of (4 + 9)?
7 + 7 = 2 8 + 8 = 4 8 + 5 = 1 6 + 9 = 3 10 + 11 = 9
IF 1,3,3=5 9,7,4=8 11,14,10=15 20,16,12=18 Than 3,6,7=?
If
5 - 3 = 13 8 - 1 = 68 6 - 3 = 24 9 - 5 = 35
Then
7 - 1 = ??