The smallest number which gives the remainder of 1 when divided of any of the numbers is the LCM of the numbers + 1 i.e. LCM + 1
Which is 61
why????
Because LCM is the smallest number divisible by all the given numbers...........and to have the remainder of 1 then add 1 to the LCM
2 = 1*2 3 = 1*3 4 = 1*2*2 5 = 1*5 6 = 1*2*3 so LCM = 1*2*2*3*5 = 60 LCM + 1 = 61
So the number is 61
61 is the smallest number The smallest number which gives the remainder of 1 when divided of any of the numbers is the LCM of the numbers + 1 i.e. LCM + 1 Which is 61
My house number is such that, when divided by 2, 3, 4, 5 or 6 it will always leave a remainder of 1.
However, when divided by 11 there is no remainder. What is my house number?
Can you find a number such that if we multiply that number by 1 or 2 or 3 or 4 or 5 or 6, then the resultant number contains same all digits (of course in a different place)
