Answer: there are different ways to solve:
Sol 1 :- (0! + 0! + 0! + 0! + 0!)! = 120
Here '!' symbol is used for factorial.
And 0! = 1
= (0! + 0! + 0! + 0! + 0!)!
= (1 + 1 + 1 + 1 + 1)!
= 5!
= 120
Sol 2 :- (cos (0) + cos (0) + cos (0) + cos (0) + cos (0))! = 120
= (cos (0) + cos (0) + cos (0) + cos (0) + cos (0))!
= (1 + 1 + 1 + 1 + 1)!
= 5!
= 120
Similarly you can replace cos (0) with tan (0).
Sol 3 :- (0!0! * 0!0!) - 0! = 120
= (0!0! * 0!0!) - 0!
= (11 * 11) - 1
= 121 - 1
= 120