I need to divide numbers from 1 to 9 into two group such that sum of numbers in one group is equal to the sum of other group. Note : 6 cannot be flipped over to make it 9.
1 2 3 4 5 6 and 7 8 6
Since summation of numbers 1-9(1 2 3 4 5 6 7 8 9) is 45 , so its impossible to divide into two equal parts. Since we cant flip over 6 to make it 9 but we can flip 9 to make it 6 and hence the solution!
Is it possible to write down 1,2,3..100 in some order (one after an other), such that the sum of any two adjacent numbers is a prime number?
You need to empty 1 mug of milk and 1 mug of water into the barrel such that * We can differentiate between water and the milk. * We can sperate milk from the water. * We cant use any kind of divider to separate water and milk.
You need to fill number in the bricks in the image below such that the top brick is sum of two brick below it.
Using all the numbers from 1 to 10, put them into pairs, so that one pair adds to 6, another pair to 7, a third pair to 9, a fourth pair to 16 and the final pair add to 17.
Two numbers are such that their difference, their sum and their product are in the ratio 1:5:24. What is the product of these two numbers?
