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a^2+b^2=c^2+d^2=2 From this we can say, a=b=c=d=±1 So, ac+bd = (±1)(±1)+(±1)(±1) = 1+1 = 2
If abcde=1 (where a,b,c,d and e are all positive real numbers) then what is the minimum value of a+b+c+d+e?
If a + b + c = 8 a.b.c = 27 then Is there exist solution/s in (a,b,c) where a, b and c are positive real numbers?