If r is a root of the equation x^2 + 2x+6 = 0 then what is the value of (r+2)(r+3)(r+4)(r+5)?

Answer 1

-126

Explanation:

First multiply (r+3)&(r+4) and other two u I'll get r^2+7r+12 in one and r^2+7r+10. In other write first one 5r+6& second one 5r+4 multiply taking 25 common u 'll get the answer .