Find four numbers so that the same answer is obtained when: (a) 4 is added to the first (b) 4 is subtracted from the second (c) the third is multiplied by 4 (d) the fourth is divided by 4.
Clue: they add up to 75.
let the numbers be abcd a+b+c+d=75 a+4=x b-4=x 4c=x d/4=x a+4=b-4 a=b-8 4c=b-4 c=b/4-1 d/4=b-4 d=4b-16 b-8+b+b/4-1+4b-16=75 6b+b/4=100 25b=400 b=16 a=16-8 a=8 c=16/4-1 c=3 d=4*16-16 d=48
What number when added to itself, subtracted from itself, multiplied by itself and divided by itself, will add up to 22.09?
What least number must be subtracted from 1739 so that the resulting number when divided by 6, 10 and 12 will leave in each case the same reminder 5?
Find three number such that?