Three coins are tossed in the air and two of the coins land with heads face upwards. What are the chances on the next toss of the coins that at least two of the coins will land with heads face upwards again?
Assuming the previous coin tosses have no influence on the outcome of any future coin tosses the probability of having atleast 2 of the 3 coins facing upwards is: [Events favoring the given event] / [Total number of possible events] Total possible events = 2*2*2 = 8. number favorable outcomes = 3!/2! + 3!/3! = 6/2 + 6/6 = 3(2 heads and 1 tail) + 1(All heads outcome) = 4. ie. Probability = 4/8 = 0.5 or 50%.
Upon tossing a fair coin five times, you get heads every time. What is the probability that in the next toss, it will land with tail?
Sachin has two coins, one of Rs. 1 denomination and the other of Rs. 2 denomination. He tosses the two coins simultaneously. What is the probability that he gets at least one head?
If you toss a coin ten times and it lands heads up every time, what is the probability that it will land heads up if you toss it again?
A) 25% B) 50% C) 60% D) 25%
