What is the probability of getting a product of 72 from three throws of a dice?

Question

A1/36

B1/24

C8/216

D6/216

Select from the options above.

Correct Option: 2  

Explanation:
Total Number of possible outcomes = 6C1*6C1*6C1 = 6*6*6 = 216
Positive outcomes must satisfy D1*D2*D3=72
Below are such values of D1, D2 and D3:
2, 6, 6
3, 6, 4
3, 4, 6
4, 6, 3
4, 3, 6
6, 6, 2
6, 4, 3
6, 3, 4
6, 2, 6

Count of positive outcome = 9
Probability = Positive outcome/Total Possible Outcomes = 9/216 = 1/24