Product of three consecutive numbers are 7980. Then the sum of these consecutive numbers would be?

Question

If the product of 3 consecutive numbers is divided by each of them in turn, the sum of the 3 quotients will be 74.
What are the numbers?

Answer 1

a×(a + 1)×(a + 2) = 7980
a×(a^2 + 3a + 2)
a^3 + 3a^2 + 2a - 7980 = 0
a = 19 therefore b = 20 and c = 21
And a + b + c = 60.