If 1 +1 = 2, 3 + 3 = 6, 13 + 24 = 40, 14 + 25 = 42 Then 41 + 52 = ?

Question

Answer 1

Ans : 102

Solution:
1 + 1 = 2
01 + 01 = (01 + 01 + 0 + 0) = 2

3 + 3 = 6
03 + 03 = (03 + 03 + 0 + 0) = 6

13 + 24 = 40
(13 + 24 + 1 + 2) = 40

14 + 25 = 42
(14 + 25 + 1 + 2) = 42

41 + 52 = ?
(41 + 52 + 4 + 5) = 102

Answer 2

If 1 +1 = 2, 3 + 3 = 6, 13 + 24 = 40, 14 + 25 = 42 Then 41 + 52 = ?

Here digits should look like tens digits so....1 will be written as 01

01+01=(01+01+0+0)=2

03+03= (03+03+0+0)=6

13+24= (13+24+1+2)=40

14+25=(14+25+1+2)=42

41+52= (41+52+4+5)= 102