Alloy A and B contains Tin and Copper in the ratio 5 : 3 and 2 : 5 respectively. In what ratio A and B should be mixed to get a new alloy containing Tin and Copper in the ratio 4 : 3?
Beaker A consists of sugar and water mixture in ratio 5:3 and beaker B has the same mixture in ratio 2:3. These two mixtures are mixed to form a new mixture containing half sugar and half water. In what ratio they must be taken?
The present ages of A,B and C are in proportions 4:5:6. Eight years ago, the sum of their ages was 66. What is the sum of present age of A and C?
Solve this without paper and pen?