Let the 2 numbers be a & b. a = 84 = 2^2 × 3 × 7 b = ? = 2 × 7 × y { because LCM = 14 = 2 × 7 } HCF = 588 = 2^2 × 7 × 3 × y y = 588/(4 × 7 × 3) = 7 Therefore b = 2 × 7^2 = 98
LCM of two numbers is 60 times their HCF. If sum of LCM and HCF is 549. If one number is 45 then what is the other number?
The L.C.M and H.C.F of two numbers are 336 and 12 respectively. If one of the number is 84 then what will be the other number?