Shaktiman saw a criminal at a distnce of 35m. When Shaktiman started chasing him, the criminal also started running. If the ratio of speeds Shaktiman to criminal is 12 : 11. Then how much distance did Shaktiman run to catch the criminal?
420m
If x- Shaktiman's speed and y- criminal's speed, t- time to run, we have 1) x/y=12/11, 2) xt-yt=35 3) xt =? from 1) x=y*12/11 considering this in 2) xt-yt=35-> yt*12/11-yt=35->yt*1/11=35->yt=385 as xt=yt+35, xt=385+35=420m xt=420m
35m*12m = 420 m For each 12m of S run, the distance between S and T will reduce to 1m. so to reduce to this 35m distance, s should run 12m for 35 times
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