Yes As per divisibility rule, sum of the digits of number must be divisible by 9. We can state that 3^n is divisible by 9 as 3^n=9*3^(n-2) where n is positive integer >1. Since it is divisible by 9, the sum of its digits is divisible by 9.
A 9-digit number has a property that the first 'n' digits are divisible by 'n'. There is no '0' in the number and all the digits in the number are distinct. What is the number?
What is the number if it is 1 less than a square number and it is not divisible by 3 or 7 (You make a square number when you multiply something by itself, so 49 is square because it is 7 times 7)
