In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?
209
Number of ways ==> (6C1 x 4C3) + (6C2 x 4C2) + (6C3 x 4C1) + (6C4) = (6C1 x 4C1) + (6C2 x 4C2) + (6C3 x 4C1) + (6C2) = (24 + 90 + 80 + 15)= 209
There are 3 boys and 4 girls. We have to arrange any 1 boy at the center and any 2 girls at corners. In how many methods these persons can be arranged.
There are 13 members in a committee having 7 men and 6 women . In how many ways a team of 4 persons can be selected in such a way that at least 1 man would be there in the team ?
There are 5 mangoes and 6 bananas. In how many different ways can a selection of fruits be made if all fruits of same kind are numbered with different tags.
