If d=2, Then minimum Sum is possible only when 10 is added 10 times ie., sum = 10×10 = 100. Therefore number of digits of the smallest sum for d=2 in terms of d is (d + 1).
The answer is d + 1
If abcde=1 (where a,b,c,d and e are all positive real numbers) then what is the minimum value of a+b+c+d+e?