Find the value of 2x^2 + 4zy + 3z^2. Where x = mean, y= median and z= mode of following number 77 104 91 97 131 48 114 119 91 117 122
58804
77,104,91,97,131,48,114,119,91,117,122 x- Mean = sum/count= 101 y- Median= middle term= 104 z- Mode= number given maximum number of times= 91 (appears 2 times) 2x^2 + 4zy + 3z^2= 2*101^2+4*91*104+3*91*2=58804
Find the value of x^2 + 3xyz + 2y^ + 3z^2 where x = Mean , y = Median and z = Mode of following numbers: 83 87 93 97 110 48 114 119 87 118 122
Find the value of x*y*2*z/5 Where x = mean, y = median and z= mode of following number 57 59 56 81 69 55 64 63 81
Find the product of one fifth of mean, two third of median and two times of mode ( i.e. you need to find 1/5*mean * 2/3*median * 2*mode ) for the following list of values?
121, 107, 91 97, 131, 147 111, 91, 119 117, 133
Find the product of mean, median and mode (i.e. you need to find mean*median*mode)for the following list of values? 23; 16; 45; 28; 18; 23; 36;
