60 cm^2
Using Pythagorean Theorem we find missing side: SQRT(17^2-15^2)=8 cm The area A=8*15/2=60 cm^2
Find the Area of the Right Angled Triangle whose hypotenuse is 11 cm and perpendicular from the right angle vertex on the hypotenuse is 6 cm.
A right triangle ABC has legs AB = 4, BC = 6, and has a semicircle O with its center on the hypotenuse tangent to the legs AB at D and BC at E. What is the radius of the semicircle?
Triangle ABC has a right angle at B. Let Q be along BC and P be along AB such that AQ bisects angle A and CP bisects angle C. If AQ = 9 and CP = 8√2, what is the length of the hypotenuse AC?
If the length of two sides of a right angled triangle measured in inches are prime numbers, and it has two adjacent sides of 12 and 13 inches long, how long must the third side be?
A circle of radius 12 is inscribed in a right triangle, dividing the hypotenuse into lengths of a and b = 44. What is the length of a?