I want to buy a $1.00 newspaper. I have just enough pennies $0.01, nickels $0.05, dimes $0.10, and quarters $0.25 to buy the newspaper in every possible exact-change combination of those coins.
How many coins do I have?
The question is not clear. If I want to make any combination possible using pennies, nickels, dimes and quarters I would need: 100 pennies 20 nickels 10 dimes 4 quarters = 134 coins. But I do not think that is what you mean.
Maria went to the bread store to buy a loaf of bread for dinner. She had 2 quarters, 4 dimes, 3 nickels and 2 pennies. The total cost of the bread $0.82. She promised to make sure she had exactly 1 coin remaining after purchase. Which coins did she have left after buying the loaf of bread?
Irene went to the store to get ice cream. She had 2 quarters, eight dimes, 3 nickels and 1 penny. The ice cream cost her $0.95. She promised not to spend 3 of her coins. Which coins did she use to buy the ice cream?
A man has 20 coins, consisting of dimes (10 cents) and quarters (25 cents). If the dimes were quarters and the quarters were dimes, he would have 90 cents more than he has now. How many dimes and quarters does he have?
There is a shop where written: Buy 1 for $1 10 for $2 100 for $3 I needed 999 and still only paid $3. How could this be financially viable for the shop-keeper?
