What is the area of the trapezoid ABCD ?
We may take a=12; b=20; c=1 and d=13 The solution of height formula is height=12 If we put the known units a, c and h into Area formula, the area of the trapezoid ABCD is [(12+1)/2].12 = 13.16 = 78
In trapezoid ABCD, the sides AB and CD are parallel and AB > CD. Point P is in the interior, dividing the trapezoid into 4 triangles with areas CPD = 2, CPB = 3, BPA = 4, APD = 5. What is AB/CD equal to?
Suppose ABCD is an isosceles trapezoid with bases AB and CD and sides AD and BC such that |CD| > |AB|. Also suppose that |CD| = |AC| and that the altitude of the trapezoid is equal to |AB|
If |AB|/|CD| = a/b where a and b are positive coprime integers, then find a^b?
In the figure shown we have a right trapezoid that was divided into two rectangles with areas of 56 and 14, and a smaller trapezoid with area of 9. What is the area of the blue triangle?
Trapezoid as shown has two parallel sides with length 5 and 15 & two diagonals with length 12 and 16. What is its area?
A right trapezoid is partitioned into 4 triangles by its diagonals, as shown:
Which colored region has a largest area?