12 &14
x^2+(x+2)^2=340 ===> positive solution is x=12 numbers are 12 &14
x^2+(x+2)^2=340 x^2+x^2+4x+4=340 2x^2+4x-336=0 x^2+2x-168=0 x^2+14x-12x-168 x(x+14)-129x+14=0 (x+14)(x-12)=0 x=12 or-14 x=12 as x is positive So the numbers are 12 and 14
If 1^3 + 2^3 + 3^3 = m^2 where m is also an integer. What are the next three consecutive positive integers such that the sum of their individual cubes is equal to a perfect square?
The average of squares of five consecutive even natural numbers is 792. What is the ratio of smallest number to largest number?
First 17 positive integers (1..17) are rearranged into a sequence such that the sum of any two adjacent terms is a perfect square. What is the sum of the first and last terms of this sequence?
