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The sum of squares of three successive integers is 5810. Sum of these integers is?
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The sum of squares of three successive integers is 5810. Sum of these integers is?
mathematical
posted
Dec 27, 2019
by
Aastha Joshi
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1 Answer
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(x-1)^2+x^2+(x+1)^2=5810
3x^2+2=5810
3x^2=5808
x^2=1936
x=44
43+44+45=
132
answer
Dec 27, 2019
by
Hanifa Mammadov
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