How many solutions are there to satisfy the equation: ABC+BCD=CBA where each letter represents one digit?
C + D = A + 10(carry) 1 + B + C = B + 10(carry) 1 + A + B = C Therefore C = 9 and A + B = 8. So the possible solutions are 1. 089 + 891 = 980 2. 179 + 792 = 971 3. 269 + 693 = 962 4. 359 + 594 = 953 5. 539 + 396 = 935 6. 629 + 297 = 926 7. 719 + 198 = 917 ie. There 7 solutions.
If a, b, and c are distinct numbers, how many solutions are there to the following equation?
How many integer solutions are there to the system of equations below and which are those solutions?
x^2+y-z = 42 x+y^2-z = 18
