The product of 3 integers x, y, z is 192. Also z is equal to 4, and p is equal to the average of x and y. What is the minimum possible value of p?
-24.5
Given: x*y*z=192 z=4 p=(x+y)/2
x*y=192/4=48 x*y=(+-) applies to all to the right 1*48=2*24=3*16=4*12=6*8=8*6=12*4=16*3=24*2=48*1 as per above minimum value of p=-24.5 when x*y=(-1)*(-48)
For real numbers x, y, what is the minimum value of
√((x – 4)2 + (y – 10)2) + √((x – 44)2 + (y – 19)2)
If abcde=1 (where a,b,c,d and e are all positive real numbers) then what is the minimum value of a+b+c+d+e?
