x + y + z = 19 1 < x < 5, 4 < y < 8, 10 < z < 14 How many outcomes are possible for integral values of x, y and z?
x, y, z and k are four non zero positive integers satisfying 1/x + y/2 = z/3 + 4/k, minimum integral value of k for integral value of x, y and z will be
