Can you find a number that lies one third of the distance between 1/3 and 2/3?

Question

Can you think of three numbers that gives a prime number as their product and also the difference between the second and first is equal to the difference between third and second?

Answer 1

Let us find a bigger multiple first. Lets multiply the numerator and denominator by 9 in both the numbers.
Now, 1/3 = 9/27
And, 2/3 = 18/27

Clearly, 12/27 lies one third on the distance between the two numbers now.

Answer 2

its 12/27 ...

Answer 3

Answer: 4/9

(2/3-1/3)/3+1/3 = (6/9-3/9)/3+3/9= 1/9+3/9=4/9

Answer 4

that number is 1/9

Answer 5

Since 12/27 reduces down to: 12/3 = 4 and 27/3 = 9
Then 4/9 is the alternative/same answer.

Or converting into decimals: .333 and .666 divided into 3rds = .333/3 = .111, then add: .111 + .333 = .444
Confirmed by 4/9 = .444

Thus .444 is also an answer.