Suppose a, b, c are real numbers and the following equation is true.
(a + b – 5)2 + (b + 2c + 3)2 + (c + 3a – 10)2 = 0
Find the integer closest to a3 + b3 + c3.
Let a1 and a2 be the roots or the equation (x- a)(x - b) = c and c != 0, then what are the roots of the equation (x - a1)(x - a2) + c = 0?
Solve the following equations -
a1+a2=8 b1-b2=6 a1+b1=13 a2+b2=8
If 124 + 0 = 15 246 + 0 = 32 357 + 0 = 40 Then 468 + 0 = ?
