You have ten stacks of identical looking gold coins. Nine of the stacks contain all real gold coins, and one of the stacks is made up entirely of fake gold coins. Each real gold coin weighs exactly 1 gram, while each fake coin weighs exactly 1.1 grams. Using a scale, how can you determine the stake of fake coins? Remember, you can use only one measurement. For example, you stake what you want on the scale to read the weight. But, you can do this only once, and once the readout is displayed it does not change if you remove any coins. You can mix the coins up in their stacks, separate them and mark them, whatever. How do you find out for sure which stake contains the fake gold coins?
In front of you, there are 9 coins. They all look absolutely identical, but one of the coins is fake. However, you know that the fake coin is lighter than the rest, and in front of you is a balance scale. What is the least number of weightings you can use to find the counterfeit coin?
You have 7 tennis balls that are all identical but one of them is slightly lighter than the others.
Using a balance scale and only two separate weightings, how can you find the light tennis ball?
You have a thousand Re. 1 coins with you. You have ten bags with you and you can put any number of coins in each of the bags. The condition is that if someone asks you for any amount between 1 and 1000, you must be able to give that amount by just giving the bag (you are not allowed to open the bag and give coins).
How will you do it?
You're given 50 gold coins before your big journey, but you decide to leave 25 of them at home before leaving. On the first day you spend 20% the gold you brought on food and you give 10 of the remaining coins to a beggar who has nothing. The king now claims 20% of all gold in the country, which everyone pays in person instantly. the next day the beggar, who didn't buy a thing, gives you all his gold back, because he felt guilty for taking it.
How many gold coins do you have left for the rest of your journey ?
Place words zero, one, two, three, four, five, six, seven, eight, nine, and ten into the puzzle below. The words may read horizontally, vertically, or diagonally. TWO and SEVEN have already been placed.
