Arrange all the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9 to give four different square numbers. (You make a square number when you multiply something by itself, so 49 is square because it is 7 times 7)
The digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 can be arranged into an addition sum to add up to almost any total, except that nobody has yet found a way to add up to 1984. However 9 digits can equal 1984 by an addition sum. Which digit is omitted?
If possible fill + or - for o and make this true, if not possible then provide the reasoning...
1 o 1/2 o 1/3 o 1/4 o 1/5 o 1/6 o 1/7 o 1/8 o 1/9 o 1/10 o 1/11 o 1/12 = 0
1 2 3 4 5 6 7 8 9 = 100 Challenge: Place + and - math symbols between the numbers above to make the equation true. Use + and - a total of three times. Do not rearrange the numbers.
