All the digits of the given number are different.
Ans: 48 1) Four digit number can be formed by using 3, 5, 6,7 Total numbers= 4! = 24
2)Four digit number can be formed by using 2, 5, 7,9 Total numbers= 4! = 24
So total four digit numbers = 24+24 = 48
Answer: 48
possible 4 digit number: 5 2 7 9 => 4! = 24 6 5 7 3 => 4! = 24
It should be 24. 9752 9725 9275 9257 9572 9527 . . .
!4 24
A four digit positive number having all non-zero distinct digits is such that the product of all the digits is least. If the difference of hundreds digit and tens digit is 1. How many possibilities are there of such number?
Using the digits 1 up to 9, two numbers must be made. The product of these two numbers should be as large as possible. All digits must be used exactly once. Which are the requested two numbers?
